20y^2+3y-2=0

Solution for 20y^2+3y-2=0 equation:

Simplifying
20y2 + 3y + -2 = 0

Reorder the terms:
-2 + 3y + 20y2 = 0

Solving
-2 + 3y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-2 + -5y)(1 + -4y) = 0

Subproblem 1
Set the factor '(-2 + -5y)' equal to zero and attempt to solve:

Simplifying
-2 + -5y = 0

Solving
-2 + -5y = 0

Move all terms containing y to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -5y = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -5y = 0 + 2
-5y = 0 + 2

Combine like terms: 0 + 2 = 2
-5y = 2

Divide each side by '-5'.
y = -0.4

Simplifying
y = -0.4
Subproblem 2
Set the factor '(1 + -4y)' equal to zero and attempt to solve:

Simplifying
1 + -4y = 0

Solving
1 + -4y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -4y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -4y = 0 + -1
-4y = 0 + -1

Combine like terms: 0 + -1 = -1
-4y = -1

Divide each side by '-4'.
y = 0.25

Simplifying
y = 0.25
Solution
y = {-0.4, 0.25}